S=P(1+r*t)
S= 10.000(1+0.26*10/12)
S=12.167 TL
Fınancıal Economıcs (ENG) — Ünite 4 Soru-Cevap
Fınancıal Economıcs (ENG) (IKT322U) soru-cevapları.
What is the future value of 10.000 TL deposited today, after 10 months? Simple interest is used and the interest rate is 26%.
What is the future value of 50.000 TL deposited today, after 9 months? Simple interest is used and the interest rate is 28%.
S=P(1+r*t)
S= 50.000(1+0.28*9/12)
S=60.500 TL
How many months does it take for 500.000 TL to sum up to 616.667 TL, with a simple interest of 35%?
S=P(1+r*t)
616.667= 500.000(1+0.35*t/12)
t=8
If the nominal interest rate is 24% compounded quarterly, what is the effective annual rate?
Using the formulation on p.112 (EAR, Effective Annualized Rate),
Calculated effective annual rate is 26.25% (0.2625)
If the nominal interest rate is 36% compounded monthly, what is the effective annual rate?
Using the formulation on p.112 (EAR, Effective Annualized Rate),
Calculated effective annual rate is 42.58% (0.4258)
What is the rate of return (interest rate) for 40.000 to sum up to 46.333 TL?
S=P(1+r*t)
46.333= 40.000(1+r*5/12)
r= 38%(0.38)
What is the future value of 1800 TL if interest is compounded annually at a rate
of 30% for two years?
S=P(1+i)^n
S=1800(1+0.30)^2
S=3.042 TL
What is the future value of 15.000 TL if interest is compounded quarterly, at a rate
of 36% for five years?
0.36/4=0.09
n=4*5=20
S=P(1+i)^n
S=15.000(1+0.09)^20
S=84.066 TL
What is the future value of 75.000 TL if interest is compounded semi-annually, at a rate
of 32% for seven years?
0.32/2=0.16
n=2*7=14
S=P(1+i)^n
S=75.000(1+0.16)^14
S=599.064 TL
What is the present value of 750.000 to be received 5 years later? Nominal interest rate is 24% and the frequency of compounding is quarterly.
0.24/2=0.12
n=4*5=20
S=P(1+i)^n
P=S/(1+i)^n
P=750.000/(1+0.12)^20
P=77.750 TL
What is the present value of 60.000 to be received 2 years later? Nominal interest rate is 24% and the frequency of compounding is monthly.
0.24/12=0.02
n=12*2=24
S=P(1+i)^n
P=S/(1+i)^n
P=60.000/(1+0.02)^24
P=37.303 TL
What is the present value of 100.000 to be received 3 years later? Nominal interest rate is 24% and the frequency of compounding is semiannually.
0.24/6=0.04
n=4*3=12
S=P(1+i)^n
P=S/(1+i)^n
P=100.000/(1+0.04)^12
P=62.460 TL
Consider a 10-year car loan with constant annual payments of 600.000 at the annual interest rate r = 0.48. What will be the present value of the loan when annual compounding is applied?
Using the formulation in Equation (3.4.3.) on p.118,
C = 600.000, r = 0.48, m = 1 and T = 10
we find the present value of the loan is 1.225.209 TL
Consider a 7-year car loan with constant semi-annual payments of 500.000 at the annual interest rate r = 0.48. What will be the present value of the loan when annual compounding is applied?
Using the formulation in Equation (3.4.3.) on p.118,
C = 500.000, r = 0.48, m = 2 and T = 7
we find the present value of the loan is 1.980.802 TL
Consider an 8-year car loan with constant quarterly payments of 200.000 at the annual interest rate r = 0.441.753.720. What will be the present value of the loan when annual compounding is applied?
Using the formulation in Equation (3.4.3.) on p.118,
C = 200.000, r = 0.42, m = 4 and T = 8
we find the present value of the loan is 1.753.720 TL
If annual compounding is applied for constant annual payments of 80.000 TL, what will be the present value of the perpetuity, if the nominal interest rate is 35%?
The present value of a perpetuity=C/(r/m)
Equation (3.5.3) on p.122
C= 80.000
r= 0.35
m=1
The present value of a perpetuity=228.571 TL
If quarterly compounding is applied for constant annual payments of 90.000 TL, what will be the present value of the perpetuity, if the nominal interest rate is 44%?
The present value of a perpetuity=C/(r/m)
Equation (3.5.3) on p.122
C= 90.000
r= 0.44
m=4
The present value of a perpetuity=818.182 TL
Assume that at year t the nominal interest rate is rt= 0.35 and the inflation rate is πt= 0.55. What will be the the real interest rate at year t?
Using the formulation Eq. (3.6.9) on p.125,
rt= 0.35
πt= 0.55
The the real interest rate at year t= -0.1290 (-12.90%)
Assume that at year t the nominal interest rate is 0.36 and the inflation rate is 0.16. What will be the the real interest rate at year t?
Using the formulation Eq. (3.6.9) on p.125,
rt= 0.36
πt= 0.16
The the real interest rate at year t= 0.1724 (17.24%)
Assume that at year t the nominal interest rate is 0.42 and the inflation rate is 0.30. What will be the the real interest rate at year t?
Using the formulation Eq. (3.6.9) on p.125,
rt= 0.42
πt= 0.30
The the real interest rate at year t= 0.0923 (9.23%)